dBm to Watts, Volts and dBµV Converter

0 dBm is 1 mW, which is 224 mV rms (632 mV peak-to-peak, 107 dBµV) into 50 Ω. Every +3 dB doubles the power and every +10 dB multiplies it by 10, so 30 dBm is 1 W.

For practitioners

Ω

Results

Power (dBm)
10 dBm
Power (dBW)
-20 dBW
Power (mW)
10 mW
Power (W)
0.01 W
Voltage (rms)
0.7071 V
Voltage (peak)
1 V
Voltage (peak-to-peak)
2 V
Level (dBµV)
117 dBµV

Voltages assume a sine wave across the stated resistance. Power in dBm does not depend on the impedance; voltage and dBµV do.

How to use the calculator

Choose the unit you have, type the value and set the resistance (50 Ω for most RF work). The results show the same signal as power in dBm, dBW, milliwatts and watts, and as voltage in rms, peak and peak-to-peak, plus its level in dBµV. The voltage figures assume a sine wave across the resistance you entered.

The definitions

dBm is power in decibels relative to one milliwatt:

PdBm=10log⁡10 ⁣(P1 mW)PmW=10PdBm/10P_{\text{dBm}} = 10\log_{10}\!\left(\frac{P}{1\,\text{mW}}\right) \qquad P_{\text{mW}} = 10^{P_{\text{dBm}}/10}

dBW uses a one-watt reference, so dBW = dBm − 30. For voltage, the rms value that delivers power P into a resistance R is:

Vrms=P RVpeak=2 VrmsVpp=22 VrmsV_{\text{rms}} = \sqrt{P\,R} \qquad V_{\text{peak}} = \sqrt{2}\,V_{\text{rms}} \qquad V_{\text{pp}} = 2\sqrt{2}\,V_{\text{rms}}

dBµV is voltage relative to one microvolt rms: dBµV = 20 · log10(V / 1 µV). Into 50 Ω it equals dBm + 107 (to within 0.01 dB).

+30 dBm1 W+20 dBm100 mW+10 dBm10 mW0 dBm1 mW-10 dBm100 µW-20 dBm10 µW-30 dBm1 µW+10 dB = 10 times the power-3 dB = about halfdBm is power compared with 1 mW. 0 dBm is one milliwatt.
Power levels on the dBm scale. Every +10 dB is ten times the power.

Reference table at 50 Ω

LevelPowerVoltage (rms)Voltage (peak-to-peak)dBµV
−174 dBm3.98e−21 W0.446 nV1.26 nV−67.0
−100 dBm0.1 pW2.24 µV6.32 µV7.0
−50 dBm10 nW0.707 mV2 mV57.0
−30 dBm1 µW7.07 mV20 mV77.0
−20 dBm10 µW22.4 mV63.2 mV87.0
−10 dBm100 µW70.7 mV200 mV97.0
0 dBm1 mW224 mV632 mV107
3 dBm2 mW316 mV893 mV110
10 dBm10 mW707 mV2 V117
20 dBm100 mW2.24 V6.32 V127
23 dBm200 mW3.16 V8.93 V130
27 dBm501 mW5.01 V14.2 V134
30 dBm1 W7.07 V20 V137
33 dBm2 W9.99 V28.3 V140
37 dBm5.01 W15.8 V44.8 V144
40 dBm10 W22.4 V63.2 V147
43 dBm20 W31.6 V89.3 V150
47 dBm50.1 W50.1 V142 V154

Two reference points are worth remembering. The thermal noise floor of a 1 Hz bandwidth at 290 K is about −174 dBm, which sets the limit for receiver sensitivity. And 23 dBm (200 mW) is the maximum output power of a power class 3 LTE handset, a level that comes up often in mobile RF work.

0 dBm-10 dBmInput+10 dBmAfter amplifier (+20 dB)+7 dBmAfter cable (-3 dB)
Gains and losses in dB add to a level in dBm.

Rules of thumb

You can estimate most conversions without a calculator:

  • +3 dB is about ×2 in power, and −3 dB is about ÷2. (Exactly, 3.01 dB.)
  • +10 dB is ×10, and −10 dB is ÷10.
  • Combine them: 13 dBm is 10 dBm + 3 dB, so 10 mW × 2 = 20 mW. 27 dBm is 30 dBm − 3 dB, so 1 W ÷ 2 = 0.5 W.
  • +6 dB doubles the voltage (and quadruples the power).
  • Gain and loss in dB add to a level in dBm (this is the basis of a power budget): a −10 dBm signal through a 20 dB amplifier and a 6 dB attenuator is −10 + 20 − 6 = +4 dBm.

Common mistakes

Adding dBm values. Two 0 dBm signals do not make 0 dBm + 0 dBm = 0 dBm, and they do not make 6 dBm either. If they are uncorrelated their powers add (1 mW + 1 mW = 2 mW), which is +3 dBm. If they are coherent and in phase their voltages add, giving four times the power and +6 dBm. Know which case you are in.

Assuming 50 Ω everywhere. dBm is independent of impedance, but the voltage is not. A scope or probe with a high input impedance does not show the voltage computed into 50 Ω unless it is terminated.

Mixing rms, peak and peak-to-peak. Instruments and datasheets quote any of the three. A 0 dBm sine wave is 224 mV rms, 316 mV peak and 632 mV peak-to-peak into 50 Ω.

Ignoring the signal type. For modulated signals such as LTE or Wi-Fi the average power and the peak envelope power differ by the crest factor (peak-to-average ratio). A power amplifier may be rated by average output power (and its linearity limit is described by the P1dB compression point) while the peak voltage is several dB higher, which matters for compression and for the voltage rating of components.

Confusing dBm with dBc, dBi and dBFS. Each decibel unit has its own reference: dBc is relative to a carrier, dBi is antenna gain relative to an isotropic radiator, and dBFS is relative to the full scale of a converter. Only dBm and dBW are absolute power.

In plain words · for students and beginners

Decibels and dBm in plain words

Why decibels exist

RF signals cover a huge range: a transmitter may put out a watt while a receiver has to detect a trillionth of a watt. A normal ruler cannot show both. Decibels use a logarithmic ruler, like the Richter scale for earthquakes, where each step is a multiplication instead of an addition. On this ruler, every +10 dB is ten times the power and every +3 dB is about double.

What dBm adds

A decibel is only a ratio. To describe an actual power level you need a starting point. dBm is decibels compared with one milliwatt: 0 dBm is 1 mW, 10 dBm is 10 mW, 20 dBm is 100 mW and 30 dBm is 1 W. An LTE phone transmitting at its maximum power of 23 dBm sends about 0.2 W.

Adding and subtracting

Gains and losses in dB simply add. A signal of -10 dBm that goes through an amplifier with 20 dB of gain and then a cable with 3 dB of loss ends up at -10 + 20 - 3 = +7 dBm, which is about 5 mW. This is why RF engineers love decibels: a whole signal chain becomes a column of additions.

Where voltage comes in

Power does not depend on the impedance, but voltage does. At 50 ohm, 0 dBm (1 mW) is about 224 mV rms. If you measure with a probe that is not terminated in 50 ohm, you will not read that voltage.

Mistakes beginners make

  • Adding two dBm numbers. Two equal signals of 0 dBm do not make 0 dBm + 0 dBm. If their powers add, you get about +3 dBm.
  • Mixing up dB (a ratio) and dBm (a level). You can add a dB value to a dBm value, but not two dBm values.
  • Mixing dBm and dBW. They are 30 dB apart.

Remember

  • +10 dB is 10 times the power. +3 dB is about 2 times.
  • 0 dBm is 1 mW, 30 dBm is 1 W.
  • Gains and losses add. Levels do not.

Levels and budgets

Measurement

Calculators

Use the attenuator calculator to set a level with a resistive pad, and the VSWR and return loss calculator to see how much power a mismatch removes from a level you have computed.

Frequently asked questions

How do I convert dBm to watts?

Divide the dBm value by 10, raise 10 to that power, and divide by 1000: P(W) = 10^(dBm/10) / 1000. For example 30 dBm is 10^3 / 1000 = 1 W, and 23 dBm is about 0.2 W.

What is the difference between dBm and dBW?

dBm is referenced to 1 milliwatt and dBW to 1 watt, so dBW = dBm − 30. A 30 dBm signal is 0 dBW.

Why does the voltage depend on impedance but dBm does not?

dBm describes power, which is the same whatever the impedance. Voltage follows from V = √(P·R), so the same 0 dBm is 224 mV rms in 50 Ω and 274 mV rms in 75 Ω.

Can I add dBm values?

Not directly. dBm values are logarithms of power, so two signals of 0 dBm combine to about +3 dBm if they are incoherent and add in power. Convert to milliwatts, add, and convert back, or add a gain in dB to a level in dBm.

References and further reading